Errata De dikke Pythagoras (1e druk)
139 = 1 + (1 + 2) × 2 + 33 × 4
Paginanummers Door een technische fout zijn enkele sommen in de paginacijfers door elkaar gehaald. Hieronder vindt u de correcte versies:
141 = 112 – 2 – 3 + 34
106 = – 1 + 122 – 3 – 3 × 4 107 = 1 × 122 – (3 + 3 × 4) 108 = 1 + 1 + 2 + 2 + 3 × 34 109 = 1 + (1 + 2) × 2 + 3 × 34 110 = 11 × (2 + 2 + 3 + 3) 111 =112 – 2 + 3 / 3 112 = 112 × (–2 + 3) 113 = 1 × 122 – 3 × 3 116 = – 1 + 122 – 3 × 3 + 4 117 = 1 + 122 – 3 – 3 118 = 1 × 122 – 3 / 3 × 4 119 = 112 – 2 + 3 × 3 120 = 112 + 2 + 3 + 3 121 = – 112 + 233 122 = 1 + 122 – 3 / 3 123 = 112 + 2 + 3 × 3 124 = 1 + 122 + 3 / 3 125 = 1 + 122 + 3 + 3 – 4 126 = – 1 × (1 + 2) × 2 + 33 × 4 127 = 112 + 2 + 3 × 3 + 4 128 = – 1 × 1 × 2 × 2 + 33 × 4 129 = 112 + 2 + 3 + 3 × 4 130 = – 1 × 1 – 2 / 2 + 33 × 4 131 = 112 + (2 + 3) × 3 + 4 132 = 1 × 1 × 2 × 2 × 33 133 = 1 + 122 + 3 + 3 + 4 136 = 1 + 122 + 3 × 3 + 4 137 = 1 × 122 + 3 + 3 × 4 138 = 1 + 122 + 3 + 3 × 4
140 = 112 – 2 × 3 + 34 142 = 112 + 23 + 3 + 4 143 = 112 + 2 + 33 – 4 144 = 1 + 122 + 3 × (3 + 4) 145 = 112 + 2 – 3 + 34 146 = 1 + 1 + 2 + 2 × 3 + 34 × 4 147 = 112 – 2 + 3 + 34 148 = 1 × 1 × 2 × 2 × 3 + 34 × 4 149 = 1 × 1 + 2 × 2 × (3 + 34) 150 = 1 + 1 + 2 × 2 × (3 + 34) 151 = 1 × (1 + 2 + 2) × 3 + 34 × 4 152 = –1 × 1 × 2 + 2 × (33 + 44) 153 = 112 – 2 × 3 + 3 + 44 155 = 1 × 1 + 22 + 33 × 4 158 = 1 + 122 – 3 + 34 + 4 159 = 1 × 122 + 33 + 4 160 = 11 × 2 + 2 × 3 + 3 × 44 161 = 1 + 122 – 3 – 3 + 44 164 = 1 + 122 + 3 + 34 + 4 165 = 11 × (2 / 2 × 3 + 3 × 4) 166 = – 1 – 1 – 2 + (2 + 3) × 34 167 = 1 × 122 + 3 / 3 + 44 168 = 112 / 2 × (– 3 / 3 + 4) 169 = 1 × 1 + (2 + 2 × 3 + 34) × 4 172 = 1 × 122 + 3 + 3 + 44 173 = 112 + 23 × 3 – 4 – 4 174 = (1 × 12 + 2) × 3 + 3 × 44 175 = (1 + (1 + 2) × 2) × (3 × 3 + 4 × 4) 176 = 1 × 1 + (22 + 3) × (3 + 4) 177 = 1 + 1 + (22 + 3) × (3 + 4) 178 = – 11 + 223 – 34 179 = 1 + (12 + 2) × 3 + 34 × 4 180 = 1 × (1 + 2) × (2 + 3) × 3 × 4 181 = 1 + (1 + 2) × (2 + 3) × 3 × 4
182 = 1 × 1 × 2 × 23 × 3 + 44
Pagina 34 | Wist Je Dat: regel 3:
183 = 1 + (1 + 22 + 3) × (3 + 4) 185 = (1 + 1) × 22 + 3 × (3 + 44)
“je kunt 2n nullen en enen …” moet vervangen worden door “je kunt 2n nullen en enen …”
186 = 11 + (22 + 3) × (3 + 4)
Pagina 105 | regels 16 en 17:
184 = 1 + 1 + 2 × 23 + 34 × 4
187 = 11 / 2 × (– 2 + 3) × 34 188 = – 1 × 1 × 2 + (2 + 3) × (34 + 4) 189 = – (1 + 1) / 2 + (2 + 3) × (34 + 4) 190 = 1 × 1 + 223 – 34 191 = 1 + 1 + 223 – 34 192 = 11 × 2 + (2 + 3) × 34 193 = 11 × 22 – 33 – 4 × 4 194 = – 1 – 1 + (2 × 23 + 3) × 4 195 = 1 × 1 + 22 × 3 × 3 – 4 196 = (1 × 1 × 2 × 23 + 3) × 4 197 = – 1 × 1 + 22 × (– 3 + 3 × 4) 198 = 1 – 1 + 22 × (– 3 + 3 × 4) 199 = 1 × 1 + 22 × (– 3 + 3 × 4) 201 = – 1 + (1 + 2) × 2 × 33 + 4 202 = 1 × (1 + 2) × 2 × 33 + 4 204 = 1 + 1 + 22 × 3 × 3 + 4 205 = 112 × 2 – 3 – 3 × 4 – 4 206 = (11 – 2) × 23 + 3 – 4 208 = (11 – 2) × 23 – 3 + 4 209 = 11 + 22 × 3 × 3 211 = – 1 + 12 × 2 × 3 × 3 – 4 212 = (1 + 1 + 22) × 3 × 3 – 4 213 = 1 + 12 × 2 × 3 × 3 – 4 214 = 1 × 1 × 22 × 3 × 3 + 4 × 4 299 = 1 × 1 – 2 × 23 + 344
“n ‒ 3/n × 360° en n ‒ 2/n × 360° ” moet vervangen worden door “n – 3/n × 360° en n – 2/n × 360°”