Engineering Circuit Analysis
9th Edition
Chapter Two Exercise Solutions
1. Convert the following to engineering notation: (a) 0.045 W = 45´10-3 W = 45 mW (b) 2000 pJ = 2000 ´10-12 = 2 ´10-9 J = 2 nJ (c) 0.1 ns = 0.1´10-9 = 100 ´10-12 s = 100 ps (d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = 39.212 fs (e) 3 Ω (f) 18,000 m = 18 ´103 m = 18 km (g) 2,500,000,000,000 bits = 2.5´1012 bits = 2.5 terabits 3
1015 atoms 102 cm 21 3 (h) 10 atoms/m 3 cm 1 m
(it’s unclear what a “zeta atom” is)
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