7π₯ + 9 = β12 π₯ = β3 π₯2 + 4 π₯ + 3 = 0 π₯1 = β3
π₯2 = β1
7π₯ + 9 β€ β12 π₯ β€ β3
π, π
π₯
(π, π) = {π | π < π < π}
(π, β) = {π₯ | π < π₯}
[π, π] = {π | π β€ π β€ π}
(ββ, π) = {π₯ | π₯ < π}
(π, π] = {π | π < π β€ π}
[π, β) = {π₯ | π β€ π₯}
[π, π) = {π | π β€ π < π}
(ββ, π] = {π₯ | π₯ β€ π}
7π₯ + 9 β€ β12 (ββ, 3]
πβ€π πβ€π
π>0
ππ β€ ππ
π
πβ€π π<0 π+π β€ π+π
7π₯ + 9 β€ β12
7π₯ β€ β21
π₯β€β
21 = β3 7
(ββ, 3]
ππ β₯ ππ
π₯ 2 + 2π₯ β 3 β€ 0 π₯ = β3 π₯ = 1 π₯ 2 + 2π₯ β 3 = (π₯ + 3)(π₯ β 1) β€ 0
(π₯ + 3)
(π₯ β 1)
(π₯ + 3)(π₯ β 1) β€ 0
(π₯ + 3) β€ 0
(π₯ β 1) β₯ 0
(π₯ + 3) β₯ 0
(π₯ β 1) β€ 0.
π₯ β€ β3
π₯β₯1
π₯ β₯ β3
π₯ β€ 1. π₯ β (ββ, β3] β© [1, β) π₯ β [β3, β) β© (ββ, 1] π₯ β β βͺ [β3,1]
π₯ β [β3,1]
ΠΠΠ‘ΠΆ = ΠΠΠ‘Π΅ 2 + 2ΠΠΠ‘Π΅ ΡΠΠ’ 3 ΠΠΠ‘Π΅1 = ΡΠΠ’3 [ΡΠΠ’3,1]
ΠΠΠ‘Π΅2 = 1