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Solutions Manuals for Calculus Early Transcendentals by James Stewart, Daniel Clegg & Saleem Watson

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FUNCTIONS AND MODELS

1.1 Four Ways to Represent a Function 1. The functions  () =  +

√ √ 2 −  and () =  + 2 −  give exactly the same output values for every input value, so 

and  are equal. 2.  () =

( − 1) 2 −  = =  for  − 1 6= 0, so  and  [where () = ] are not equal because  (1) is undefined and −1 −1

(1) = 1. 3. (a) The point (−2 2) lies on the graph of , so (−2) = 2. Similarly,  (0) = −2,  (2) = 1, and  (3)  25.

(b) Only the point (−4 3) on the graph has a ­value of 3, so the only value of  for which () = 3 is −4. (c) The function outputs () are never greater than 3, so () ≤ 3 for the entire domain of the function. Thus, () ≤ 3 for −4 ≤  ≤ 4 (or, equivalently, on the interval [−4 4]). (d) The domain consists of all ­values on the graph of : { | −4 ≤  ≤ 4} = [−4 4]. The range of  consists of all the ­values on the graph of : { | −2 ≤  ≤ 3} = [−2 3]. (e) For any 1  2 in the interval [0 2], we have (1 )  (2 ). [The graph rises from (0 −2) to (2 1).] Thus, () is increasing on [0 2]. 4. (a) From the graph, we have  (−4) = −2 and (3) = 4.

(b) Since  (−3) = −1 and (−3) = 2, or by observing that the graph of  is above the graph of  at  = −3, (−3) is larger than  (−3). (c) The graphs of  and  intersect at  = −2 and  = 2, so  () = () at these two values of . (d) The graph of  lies below or on the graph of  for −4 ≤  ≤ −2 and for 2 ≤  ≤ 3. Thus, the intervals on which  () ≤ () are [−4 −2] and [2 3]. (e)  () = −1 is equivalent to  = −1, and the points on the graph of  with ­values of −1 are (−3 −1) and (4 −1), so the solution of the equation  () = −1 is  = −3 or  = 4. (f) For any 1  2 in the interval [−4 0], we have (1 )  (2 ). Thus, () is decreasing on [−4 0]. (g) The domain of  is { | −4 ≤  ≤ 4} = [−4 4]. The range of  is { | −2 ≤  ≤ 3} = [−2 3]. (h) The domain of  is { | −4 ≤  ≤ 3} = [−4 3]. Estimating the lowest point of the graph of  as having coordinates (0 05), the range of  is approximately { | 05 ≤  ≤ 4} = [05 4]. 5. From Figure 1 in the text, the lowest point occurs at about ( ) = (12 −85). The highest point occurs at about (17 115).

Thus, the range of the vertical ground acceleration is −85 ≤  ≤ 115. Written in interval notation, the range is [−85 115]. c 2021 Cengage Learning. All Rights Reserved. May not be scanned, copied, or duplicated, or posted to a publicly accessible website, in whole or in part. °

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