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apantiseis-nautikes-mixanes-epal-2026

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12:15

277 6.6.5 1), 2), 3), 4) ονομαστικά

277 6.6.6 1), 2), 3)

ΣΕΛ 89 3.4.1 1), 2), 3), 4)

ΘΕΜΑ Γ

Γ1

ΣΕΛ 153 5.3.4 Η ελλειπτική

Γ2

z=8

VH=12,56m³

D=100cm=1m

ω=9,42 rps

s, ce

α)

A = πD²/4 = 3,14·1²/4 = 3,14/4 = 314/400 = 0,785m²

VH = z·Vh → 12,56 = 8·Vh → Vh = 12,56/8 = 1256/800 = 1,57m³

Vh = A·s → 1,57 = 0,785·s → s = 1,57/0,785 = 1570/785 = 2m

β)

ω=π·n/30 → 9,42=3,14·n/30 → 9,42·30=3,14·n→ n = 9,42·30/3,14 = 3·30 = 90rpm

ce=s*n/30=2*90/30=180/30=6m/s

ΘΕΜΑ Δ

κ=2

Ni=75000KW

Nr=15000KW

pi=25bar

m’ B=3kg/s

ηe=0,5

ω=10rps

α) Ne σε KW

β) pe σε bar

γ) Θu σε KJ/kg

δ) Md σε KWm

ε) VH σε m³

α) Ne = Ni - Nr → Ne = 75000 - 15000 = 60000KW

β) ηm = Ne/Ni = 60000/75000 = 60/75 = 0,8 = 80%

ηm = Pe/Pi → 0,8 = Pe/25 → Pe = 0,8·25 → Pe = 20bar

γ) ηe = Ne/(m’ B·Θu) → 0,5 = 60000/(3· Θu) → 0,5 = 20000/Θu→ Θu·0,5 = 20000

→ Θu = 20000/0,5 = 200000/5 = 40000 KJ/kg

δ) Md = Ne/ω = 60000/10 = 6000KNm

ε) Pe = (π·k·Md)/VH → 20·10⁵ = (3,14·2·6000·10³)/VH → 20·10⁵ VH = 3,14·2·6000·10³

→ VH = (3,14·2·6000·10³)/(20·10⁵) = (3,14·2·6000)/(20·102)=(3,14·2·6000)/(20·100) = =3,14·2·3= 18,84m³

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apantiseis-nautikes-mixanes-epal-2026 by Εφημερίδα των Συντακτών - Issuu